Unformatted text preview: 2 2 12 3 3 4 3 2 2 f x x x x x ′ === +so the critical points are at x = 2, x =  2 Sign graph shows f is > 0 on [2, 2] [hence f increasing there: a)] and < 0 on ( ] [ 29 , 2 2, and∞ +∞ [b)] ( 29 6 f x x ′′ = which is > 0 on ( ] ,0∞ [hence graph is concave up there: c)]and < 0 on [ 29 0, +∞ [hence graph is concave down there: d)] and since f ′′ changes sign at x = 0, that is the xcoordinate of the inflection point....
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 Fall '08
 STAFF
 Calculus, Chain Rule, Derivative, Limits, Convex function, Concave function

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