Unformatted text preview: This is based on a partially correct solution provided by a student. Instead of first obtaining an equation for the tangent line to the curve at an arbitrary point x on the real line, we will obtain an equation for the line throught the point (2,0) with slope provided by that of the tangent line at any point ( x , f ( x )) on the curve Plainly, this is given by , or in slopeintercept form, , after routine algebra. Since the line defined by this equation also contains the point ( x , f ( x )), we must have . Consequently, as in the first solution, Thus,...
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 Fall '08
 STAFF
 Calculus, Vector Space, partially correct solution

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