This preview shows page 1. Sign up to view the full content.
Unformatted text preview: sin kx cos x + cos kx sin x ) lim k cos kx sin x = 0 lim k cos kx = 0 or sin x = 0 . By (*), cos kx does not tend to 0, so sin x = 0, implying that x = m . Consequently, if x = m , then lim k sin kx is not 0 and the series k =1 sin kx does not converge by the n th term test, which proves (b)....
View Full Document
- Fall '11