Chem Differential Eq HW Solutions Fall 2011 149

Chem Differential Eq HW Solutions Fall 2011 149 - gs H (1...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Section 8.4 The Hankel Transform with Applications 149 9. (a) The chain starts to move from rest with an initial velocity of v ( x )= x . (b) We have A 0 and B ( s )= 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: gs H (1 /z )( s ) = 2 gs 2 . So u ( x, t ) = 2 g sin g 2 st J ( xs ) 1 s ds. 13. Similar to Example 1....
View Full Document

This note was uploaded on 12/22/2011 for the course MAP 3305 taught by Professor Stuartchalk during the Fall '11 term at UNF.

Ask a homework question - tutors are online