Unformatted text preview: a 1 = a 3 = a 5 = Â·Â·Â· = a 2 k +1 = Â·Â·Â· = 0; a is arbitrary; a 2 =2 2 a =a , a 4 =2 4 a 2 = 1 2! a , a 6 =2 6 a 4 =1 3! a , a 8 =2 8 a 6 = 1 4! a , . . . a 2 k = (1) k k ! a . So y = a âˆž Â± k =0 (1) k k ! x 2 k = a âˆž Â± k =0 (x 2 ) k k ! = a ex 2 ....
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 Fall '11
 StuartChalk
 Power Series, Taylor Series, Zagreb, Highways in Croatia, xm

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