Unformatted text preview: a 6 = 0 ,Y = aX + b,so P ( Y â‰¤ y ) = P ( aX + b â‰¤ y ) = P ( X â‰¤ yb a ) = F ( yb a ) 2.1: 4. Solution: Let H = Î»F + (1Î» ) G , then when x â†’ âˆž ,H ( x ) â†’ when x â†’ + âˆž ,H ( x ) â†’ 1. And since F and G are nondecreasing and rightcontinuous, so H is also nondecreasing and rightcontinuous. 1...
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 Fall '08
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 Probability, Probability theory, Probability space

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