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exam_review

# exam_review - i y ss t = G j sin t" G j ii Bode plots G...

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ME 375 Final Exam Review Material 1 When viewing on the course blog, the underlined links below will take you to example solution videos. 1. Modeling a. Mechanical systems (chapter I) b. Electrical systems (chapter IX) c. Electro-mechanical systems (chapter X) d. Hydraulic systems (chapter XII) e. Block diagrams (chapter XI) i. Constructing block diagrams from component transfer functions ii. Developing system transfer functions from system block diagram 2. Dynamic response (chapters II- VIII) a. Review of Laplace transform fundamentals b. Transfer function (TF) : forced response, Y s ( ) = G s ( ) U s ( ) c. Transient response to unit step input : i. First-order systems: relating TF poles to 2% settling time t s ii. Second-order systems: relating TF poles to 2% settling time t s and % overshoot, % OS iii. System design based on t s and % OS (the “wedge”) d. Steady-state response to unit step input : final value theorem y ss = G 0 ( ) e. Steady-state response to unit sinusoidal input
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Unformatted text preview: : i. y ss t ( ) = G j ! ( ) sin t + " G j ( ) ( ) ii. Bode plots: G j ( ) dB and ! G j " ( ) vs. f. Stability : ALL poles of TF in the left-half of complex plane 3. Feedback control (chapters XIV-XVI) a. Closed-loop TF : G CL s ( ) = G OL s ( ) / 1 + G OL s ( ) ! " # \$ b. PID controllers : G OL s ( ) = G C s ( ) G P s ( ) = K P + K I s + K D s ! " # \$ % & G P s ( ) c. Closed-loop characteristic equation in terms of a single gain variable K : D CL s ( ) = 1 + K N s ( ) D s ( ) = d. Constructing root locus (RL) plots : using the eight RL rules e. Design of PID controllers based on unit step response : GIVEN design response specifications (%steady-state error 1 ! G CL ( ) " 100 , t s and % OS ). FIND PID controller gains. " Chapter numbers I through XVI refer to lecture notes. Y s ( ) ! R s ( ) G C s ( ) G P s ( ) G OL s ( )...
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