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Unformatted text preview: the angular velocity and angular acceleration of the bar as: ϖ = ˙ θ k = 0.2k α = ˙ ˙ θ k = 0.1k Using the above information we can now write: v B = v A + ϖ × r B/A = 3i + 0.2k ( 29 × 2cos θ i + 2sin θ j ( 29 = 3i + 0.2 ( 29 2cos θ ( 29 j + 0.2 ( 29 2sin θ ( 29i ( 29 = 30.4sin30 ° ( 29 i + 0.4cos30 ° ( 29 j = 2.80i + 0.346j ( 29 ft/ sec a B = a A + α × r B/A + ϖ × ϖ × r B/A ( 29 = 4j +0.1k ( 29 × 2cos θ i + 2sin θ j ( 29 + 0.2k ( 29 × 0.2k ( 29 × 2cos θ i + 2sin θ j ( 29 [ ] = 4j +0.1 ( 29 2cos θ ( 29 j +0.1 ( 29 2sin θ ( 29i ( 29 + 0.2k ( 29 × 0.2 ( 29 2cos θ ( 29 j + 0.2 ( 29 2sin θ ( 29i ( 29 [ ] = 4 + 0.2sin30 ° ( 29 i +0.2cos30 ° ( 29 j + 0.2 ( 29 2 2cos θ ( 29i ( 29 + 0.2 ( 29 2 2sin θ ( 29j ( 29 = 4 + 0.2sin30 ° 0.2 ( 29 2 2cos θ ( 29 [ ] i +0.2cos30 °0.2 ( 29 2 2sin θ ( 29 [ ] j = 4.03i0.213j ( 29 ft/ sec 2...
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 Fall '09

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