Unformatted text preview: Yield strength 25,000 psi (175 MPa) Tensile strength 50,000 psi (350 MPa) Strength coefficient, K 60,000 psi (400 MPa) Strain hardening index, n 0.15 The fracture occurred when ε =0.35. (a) Determine the resilience. (b) Calculate the value of ductility. (c) Determine the value of toughness. 3. Hardness problem (see Figure 2.12 in the textbook) (a) Solve textbook 2.54. (b) Solve textbook 2.57. 4. A bar 0.5 m long is stretched to the strain of 0.12 and then stress relieved. The yield stress of this material is 600 MPa and E=200 GPa. The plastic deformation is described by the strain hardening equation σ = K ε n with K=760 MPa and n=0.2. Determine the length of the bar after the external stress is relieved....
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- Fall '09
- Tensile strength, yield strength, engineering stress-strain curve, tensile strength TS