hw6sol - ME 363 1. Homework #6 = 4 150 = 600 max = 0.7 (...

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ME 363 Homework #6 Solutions 1. () max 4 150 600 0.7 UTS t 0.7 320 1 600 134,400 N = Ρ= × × × = A A
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2. 2 Consider an infinite strip, then you can calculate the scrap by considering the half of the strip width with blanks laid out with the clearance between them 20 21 20 105.84 4 scrap rate= 0.252 20 21 420 2 π ×−× == × 5.2%
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3. a) 3 3 6 3 6 4- 3 1 0.5 29 10 0.0359 4 - 3 1 0.5 40,000 520.55 4 - 3 1 0.0182 29 10 0.0359 0.0182 0.473 40,000 ii i i i i RR Y R Y ET ET RY ET ET ET ET ET ET ET Ri ⎛⎞ =+ ⎜⎟ ⎝⎠ ×× i = + × ∴= == i i 0.946 f n Di n = b) () 2 0.473 / 0.0359 1 90 27.35 0.948 2 0.5 / 0.0359
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hw6sol - ME 363 1. Homework #6 = 4 150 = 600 max = 0.7 (...

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