Exam2F10_sol

# Exam2F10_sol - Name Section 9:30_Ariyur 11:30_Savran...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Name: _______________________________ Section: 9:30_Ariyur 11:30_Savran 1:30_Chiu ME 365 EXAM 2 Thursday November 4, 2010 6:30‐7:30 p.m. EE 129 PROBLEM 1 2 3 4 TOTAL POINT DISTRIBUTION SCORE 35 points 35 points 40 points 40 points 150 points Percentage: 2/3 Total = Don’t forget your name and please circle your section instructor. Exam is 6 pages including this cover page: make sure you’re not missing any pages. If you use extra pages, indicate on the problem page that you’re continuing onto an extra page. Pay attention to units. Explain your reasoning. Correct answer with wrong explanation = no credit. 1 & I2,BS\$#&5H&C.'4:!':+!([email protected]%*!05((+)+%'5.2!+D-.'5\$%3!\$)!()+D-+%4,!)+31\$%3+!(-%4'5\$%3! @5':!':+5)!E\$0+!/.*%5'-0+!05.*)./3!F/.'4:!':+!%-/+).23!\$%!':+!*).1:[email protected]':!':+!2+''+)3!(\$)! ':+!+D-.'5\$%[email protected]<!& .6 ! G6 ! 46 06 ! ! ! ! (,S4*+,-%!! .I3,3J!F':5)0!\$)0+)!3,3'+/KKK9L0EM0+4.0+!)\$22!\$((H! GI3,3N!F%\$'4:!(52'+)H! 4I3,3"!F3+4\$%0!\$)0+)!KJL0GM0+4!)\$22!\$((O!)+3\$%.%4+!1+.=H! 0I3,3B!F3+4\$%0!\$)0+)!KJL0GM0+4!)\$22!\$((O!%\$!)+3\$%.%4+!1+.=H! ! ! & & & & & ! & B! I2,BS\$#&/ P:+!E\$0+!05.*)./!\$(!':+!()+D-+%4,!)+31\$%3+!\$(!.%!.44+2+)\$/+'+)!53!*5;+%[email protected]!! Bode Diagram! 0! Magnitude 20! (dB)! 40! 60! 80! 1000! ! Phase (deg)! 45! 90! 135! 1801 ! 0! 1 ! 1 0! 2 ! 3 ! 1 0 Frequency ! (rad/sec)! 1 0! 4 ! 1 0! 5 ! & "H Q5;+!':+!3'.'54!3+%35'5;5',!.%0!%.'-).2!()+D-+%4,!.%0!0./15%*!).'5\$!\$(!':+! .44+2+)\$/+'+)6!& & XT0H5&Y>0S,QXTE>0ALZ[&-"*42"S&U2\$\4\$-)3&T5000&2"[email protected]\$)&YU2,#&G8"@\$&GS,*&"*&E.0& [email protected][&A"#G+-Q&2"*+,T0H<&YXR>! TXZ& & BH R:.'!53!':+!)+3\$%.%4+!()+D-+%4,S!?.24-2.'+!.%.2,'54.22,O!TUP!()\$/!':+!*).1:6& [email protected],-"-*&U2\$\4\$-)3&T" -# &Y5E>! >ZTF0FH50;]2"[email protected]\$)& ! 46 E,!:[email protected]!/-4:!53!.%!5%1-'!.'!"LLLL!).0M3+4!.''+%-.'+0!G,!':53!3+%3\$)!)+2.'5;+!'\$!.%! 5%1-'!.'!"LL).0M3+4S! L3&"&U")*,2&,U&500&YEC0ALZ& & 06 V!1.335;+!(5)3'!\$)0+)!(52'+)!F3'.'54!3+%35'5;5',!A"H!.''+%-.'+3!':+!\$-'1-'!\$(!':53! .44+2+)\$/+'+)!G,!BL0E!/\$)+!.'!BLLL).0M3+46!R:.'!53!5'3!'5/+!4\$%3'.%'! .11)\$85/.'+2,S! V!(5)3'!\$)0+)!(52'+)!:.3!.!)\$22!\$((!\$(!KBL0EM0+4.0+I35%4+!)\$22!\$((!G+*5%3!.11)\$85/.'+2,!.'!':+! 4)5'54.2!()+D-+%4,O!" )2T>002"[email protected]\$)&+-&*[email protected]&)"@\$H&?+#\$&),[email protected]*"-*T5R>00T0H00<&@\$),[email protected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j ! ) = G F (j ! ) " G S (j ! ) " L 1,2 = G F (j ! ) " G S (j ! ) " Z Z in 2 +Z out 1 in 2 (5 + 50, 000j ! ) 0.02 10 0 1+ 0.01 ! j = " " (5 + 50, 000j ! ) 1+ 0.001 ! 1+ 0.01 ! j j 300 + 1+ 0.01 ! j = = ! ! ! ! ! ! ! ! ! ! ! 2 (5 + 50, 000j ! ) " (1+ 0.001 ! )(1+ 0.01 ! ) (5 + 50, 000j ! ) + 300(1+ 0.01 ! ) j j j = ! 2 " (1+ 0.001 ! )(1+ 0.01 ! ) j j 1 300(1+ 0.01 ! ) j 1+ (5 + 50, 000j ! ) 2 (5 + 50, 000j ! ) " (1+ 0.001 ! )(1+ 0.01 ! ) (305 + 50, 003j ! ) j j ! !"# \$%&'()*+,-.*,/%00%1(&2,34-(5*,/(0-*+,&*-1%+6, , 7*-*+8(&*,-.*,/+*9:*&4;,+*'<%&'*,/:&4-(%&,%/,-.*,3=%5*,%<>38<,4(+4:(-?/(0-*[email protected], , Z F1 " Z F2 " = R, Z I1 V1 Z =# Vin Z = = F I 1 C1 ! j + R1 = C1 ! j RC1 ! j RC1 ! j R =# =# =# 1 R1 1 ! + Cj 1 R1 1 ! + Cj 1 j! + C1 ! j 1 , ( R 2 ) + ( 2j ! ) 1 C Z Vo =# V1 Z F2 1 R1 1 ! + Cj =# Z I2 = R2 1 ( R 2 ) + ( 2j ! ) 1 C R2 I2 , =# 1 1 =# 1 R 2C 2j ! + 1 0. j ! + 1 V1 Vo RC1 ! j RC1 ! j V \$ o= % = = Vin Vin V1 ( + R 1 1 ! )( + R 2C 2j ! ) 1 Cj 1 ( + j ! )( + 0. j ! ) 1 1 1 , !\$# A:30(-3-(5*0;,)*'4+(=*,-.*,/:&4-(%&,%/,-.*,3=%5*,B<>C8<,4(+4:(-,!!"#!\$%&''()*+,\$%&'')+-) .&/0)%&''#@,,"3'*),%&,-.*,<+*5(%:',3&'1*+D,)*-*+8(&*,-.*,<3'',=3&),!123\$+44) 4-5625/1"5'#,/%+,-.*,3=%5*,%<>38<,4(+4:(-?/(0-*[email protected], , T his is a band- pass f ilter. 1 1 = = 1 [rad / sec] 6 , R 1 1 0.1! 1 " 1 ! 1 #6 C 0 0 0 1 1 L P cut- of f f requency is = = 1 [rad / sec] 0 6 R 2C 2 1! 1 " 0.1! 1 #6 0 0 HP cut- of f f requency is \$ Pass band: 1to 1 [ ad/sec] 0r , !7# 7*-*+8(&*,-.*,530:*,%/,-.*,+*'('-3&4*,7,&**)*),-%,2(5*,3,-%-30,23(&,%/,EF,/%+,-.*,3=%5*, B<>C8<,4(+4:(-?/(0-*[email protected], , 1 has gain of 1in the pass- band 1+ 0.1 " j In order f or the combined f ilter has gain of 1 in the pass- band, the high- pass f ilter 0 , need to have a gain of 1 in the pass- band. 0 L ow - pass f ilter ! R C 1j " is R C 1 1+ j " R = 1 6 = 1[M '] 0 T he pass- band gain of the high- pass f ilter ! # R C 1 = R \$ 1 % 1 !6 = 1 00 0 & ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online