ChemEquilibriumEP2SolnME501F2011

ChemEquilibriumEP2SolnME501F2011 - ME 501 Chemical...

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ME 501 Chemical Equilibrium Example Problem 2 Calculate the equilibrium constant for the reaction 22 2 ON N O at 2600 K. Use the RRHO model for the diatomic molecules and use the following data: rot (K) vib (K) ( D 0 /hc ) (cm -1 ) O 2 2.08 2280 41,300 N 2 2.88 3390 78,700 NO 2.44 2740 52,400 Consider the following electronic levels: O 2 : Level 0: gh c c m 00 1 30 ,( / ) Level 1: c c m 11 1 27 , ( / ) ,920 N 2 : Level 0: 1 1, ( / ) 0 c c m  NO: Level 0: 1 2, ( / ) 0 c c m Level 1: 1 2 , ( / ) 121 c c m Compare with the table value of 4.912x10 -3 . For the reaction AB CD C D   , 0, exp , CC DD R RA A B B C C D D B NN ZZ DDDD kT      For the equilibrium reaction 2 N O ,  1 2 41,300 78,700 2 52,400 15,200 RO N N O R R D cm hc  Now calculate the ratio of partition functions: 2 C D N O Z Z Z
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22 2 2 2 2 2 2 2 2 2 2 2 2 2 2 ,, , , , , , , , , , , , trans elec vib rot nuc trans NO elec NO vib NO rot NO nuc NO NO O N trans O trans N elec O elec N vib O vib N rot O rot N nuc O nuc N
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ChemEquilibriumEP2SolnME501F2011 - ME 501 Chemical...

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