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Differential Equations Lecture Work Solutions 46

Differential Equations Lecture Work Solutions 46 - 2 1 0 1...

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-10 -5 0 5 10 -2 -1 0 1 2 -10 -5 0 5 10 -2 -1 0 1 2 Figure 31: Sketch of the periodic extension of the odd extension of f ( x ) (problem 5) 5. f ( x ) = 1 0 < x < π/ 2 0 π/ 2 < x < π Expand in series of sin nx f ( x ) π n =1 b n sin nx b n = 2 π π 0 f ( x ) sin nx dx = 2 π π/ 2 0 1 · sin nx dx
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