Differential Equations Lecture Work Solutions 52

Differential Equations Lecture Work Solutions 52 - To...

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To compute the coefficients, we need the integral Z L 0 cos 3 π L x sin L xdx Using the trigonometric identity sin a cos b = 1 2 (sin( a + b )+s in ( a b )) we have 1 2 Z L 0 sin ( n +3) π L x +s in ( n 3) π L x ! dx Now for n 6 = 3 the integral is 1 2 cos ( n +3) π L x ( n +3) π L | L 0 1 2 cos ( n 3) π L x ( n 3) π L | L 0 or when recalling that cos =( 1) m L 2 π ( n +3) h ( 1) n +3 1 i L 2 π ( n 3)
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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