Differential Equations Lecture Work Solutions 57

Differential Equations Lecture Work Solutions 57 - Take ln...

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Take ln of both sides 2 π λ =0 2 π λ =0 λ =0 λ =0 not possible not possible Thus trivial solution if λ< 0 4. 1 r ∂r r ∂u ∂r ! + 1 r 2 2 u ∂θ 2 =0 u ( a, θ )= f ( θ ) u ( r, 0) = u θ ( r, α )=0 u ( r, θ )= R ( r )Θ( θ ) Θ 1 r ∂r r ∂R ∂r ! + 1 r 2 R 2 Θ ∂θ 2 =0
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