Differential Equations Lecture Work Solutions 64

Differential Equations Lecture Work Solutions 64 - 6 b The...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 6 b. The only difference between this problem and the previous one is the boundary condition a0 u(a, θ) = f (θ) = + 2 ∞ n=1 (an a−n cos n θ + bn a−n sin n θ) ⇒ a0 , an a−n , bn a−n are coefficients of Fourier series of f a0 = 1 π an a−n = π −π 1 π f (θ ) d θ π −π f (θ) cos n θ d θ 1π f (θ) sin n θ d θ π −π Divide the last two equations by a−n to get the coefficients an and bn . bn a−n = 64 ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online