Differential Equations Lecture Work Solutions 78

Differential Equations Lecture Work Solutions 78 - 2C e2t +...

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⇒− 2 Ce 2 t + k 3 π L ± 2 = Ce 2 t = e 2 t " 2+ k 3 π L ± 2 # C =1 C = 1 k 3 π L 2 2 denominator is not zero as assumed in the problem.
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