Differential Equations Lecture Work Solutions 117

Differential Equations Lecture Work Solutions 117 - 1 b. +...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
1b . Θ 0 + µ Θ=0 Z 0 λZ =0 r ( rR 0 ) 0 +( λr 2 µ ) R =0 Z (0) = Z ( H )=0 | R (0) | < ⇓⇓ µ m = m 2 Z n =s in H z Θ m = sin cos λ n = H 2 m =1 , 2 , ··· r ( rR 0 ) 0 + H ± 2 r 2 m 2 ! R µ 0 =0 extra minus sign Θ 0 =1 R nm = I m H r u ( r, θ, z )= X m =0 X n =1 ( a nm cos + b nm sin )s in H zI m H r ± u r ( a, θ, z )= γ ( θ, z )= X m =0 X n =1 ( a nm cos + b nm sin )s in H z · H I 0 m H a ± | {z } constant a nm H I 0 m H a ± = R 2 π 0 R H 0 γ ( θ, z )cos sin H zdzdθ R 2 π 0 R H 0 cos 2 sin 2 H zdzdθ a nm = R 2 π 0 R
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

Ask a homework question - tutors are online