Differential Equations Lecture Work Solutions 189

Differential Equations Lecture Work Solutions 189 - 1d. uxx...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
1d. u xx + xu yy =0 A =1 B C = x 4 = 4 x> 0i f x< 0 hyperbolic x = 0 parabolic < 0 0 elliptic Parabolic x u xx = 0 already in canonical form Hyperbolic 0L e t ζ = x 4 =4 ζ> 0 dy dx = ± 2 ζ 2 = ± ± ζ Note: dx = dy = ± ± ζ ( ) y ± 2 3 ζ 3 / 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

Ask a homework question - tutors are online