Differential Equations Lecture Work Solutions 197

Differential Equations Lecture Work Solutions 197 - = 1 , B...

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3. a. 2 u ∂t 2 + 2 u ∂x 2 + ∂u ∂x = e kt A =1 ,B =0 ,C =1 . The discriminant ∆ = 0 2 4 · 1 · 1= 4 < 0 Therefore the problem is elliptic. 3. b. 2 u ∂x 2 2 u ∂x∂y + ∂u ∂y =4 A
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Unformatted text preview: = 1 , B = 1 , C = 0 . The discriminant = ( 1) 2 4 1 0 = 1 &gt; Therefore the problem is hyperbolic. 197...
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