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Unformatted text preview: f ( x ) = u ( x , 0) = 1 2 c e 2 x + K Therefore K = f ( x ) 1 2 c e 2 x Plug this K in the solution u ( x, t ) = 1 2 c e 2 x + 2 ct + f ( x ) 1 2 c e 2 x Now substitute for x from the characteristic curve u ( x, t ) = 1 2 c e 2 x + f ( x ct ) 1 2 c e 2( x ct ) 232...
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 Fall '08
 BELL,D

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