Unformatted text preview: f ( x ) = u ( x , 0) = 1 2 c e 2 x + K Therefore K = f ( x ) − 1 2 c e 2 x Plug this K in the solution u ( x, t ) = 1 2 c e 2 x + 2 ct + f ( x ) − 1 2 c e 2 x Now substitute for x from the characteristic curve u ( x, t ) = 1 2 c e 2 x + f ( x − ct ) − 1 2 c e 2( x − ct ) 232...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.
 Fall '08
 BELL,D

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