Differential Equations Lecture Work Solutions 237

Differential Equations Lecture Work Solutions 237 - dx dt =...

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4 . TheODEsinth iscaseare dx dt =2 u du dt =0 with u ( x, 0) = f ( x )= 1 x< 0 1+ x L 0 <x<L 2 L<x a. Since the frst ODE contains x , t and u ,weso lvethesecondODEfrst u ( x, t )= u ( x (0) , 0) = f ( x (0))
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Unformatted text preview: dx dt = 2 f ( x (0)) The solution is x = x + 2 tf ( x )-5 5 10 15 20 25 0.5 1 1.5 2 2.5 3 3.5 4 x t Figure 46: Characteristics ±or problem 4 237...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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