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Unformatted text preview: + c ) ( x ct + c ) t  {z } c d v x = F ( x ct ) + Z t f ( x ct + c, ) ( x ct + c ) ( x ct + c ) x  {z } 1 d Substitute these two derivatives into the left side of the equation and Fnd that the only term left is f ( x, t ) which is on the right. We can also check the initial condition by substituting t = 0 in the solution. In this case the integral is zero and we get F ( x ). 240...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.
 Fall '08
 BELL,D

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