Unformatted text preview: x ( t ) = 1 c t + ξ The solution of the other ODE v ( x ( t ) , t ) = G ( ξ ) Solve for ξ and substitute in v to get v ( x, t ) = G x − 1 c t ± Now change the variables back v ( x, t ) = G t − 1 c x ± . 242...
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- Fall '08
- initial condition, easiest way, characteristic equation, vt + cvx