Unformatted text preview: t 0.8 0.6 ρ =4 xs =(37/3)t 0.4 0.2 ρ =3 0 −0.2
−2 −1 0 1 2 3 4 x 5 6 7 8 Figure 49: Characteristics for problem 2
Thus xs (0) = 0 and the shock characteristic is
xs = 37
t
3 See ﬁgure for the characteristic curves including the shock’s. The solution in region I above
the shock chracteristic is ρ = 4 and below (region II) is ρ = 3. 267 ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.
 Fall '08
 BELL,D

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