Differential Equations Lecture Work Solutions 270

Differential Equations Lecture Work Solutions 270 - = 3 t +...

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-5 0 5 10 15 20 25 30 35 40 45 2 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3 x=t-1 x=12t-1 u=(x+1)/(4t) u=2 u=3 Figure 50: Solution for 4 5. u t + uu x =0 u ( x, 0) = 2 x< 2 3 x> 2 fan du dt =0 u ( x, t )= u ( x 0 , 0) dx dt = u = u ( x 0 , 0) x = tu ( x 0 , 0) + x 0 For x 0 < 2 x =2 t + x 0 x 2 t< 2 For x 0 > 2 x
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Unformatted text preview: = 3 t + x x 3 t &gt; 2 x = t u ( x , 0) + x at discontinuity x = 2 we get x = t u + 2 u = x 2 t 270...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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