Differential Equations Lecture Work Solutions 272

Differential Equations Lecture Work Solutions 272 - 272

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-5 0 5 10 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 x=t+1 u=x/(1+t) u=0 u=1 Figure 53: Solution for 6 dx dt = u = u ( x 0 , 0) x = tu ( x 0 , 0) + x 0 For x 0 < 0 x = t · 0+ x 0 x = x 0 u =0 0 x 0 < 1 x = tx 0 + x 0 x = x 0 (1 + t ) u = x 0 = x 1+ t 1 x 0 x = t + x 0 x = t + x 0 u =1 Basically the interval [0, 1] is stretched in time to [0, 1 + t].
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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