Differential Equations Lecture Work Solutions 276

Differential Equations Lecture Work Solutions 276 - ) = 1 c...

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1a. u ( x, t )= F ( x ct ) Use the chain rule: ∂u ∂t = c dF ( x ct ) d ( x ct ) at t =0 ∂u ∂t = c dF ( x ) dx 1b. ∂u ∂x = dF ( x ct ) d ( x ct ) · 1 at x =0 ∂u ∂x = dF ( ct ) d ( ct
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Unformatted text preview: ) = 1 c dF ( ct ) dt = F ( ct ) diferentiation with respect to argument 276...
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