Differential Equations Lecture Work Solutions 283

Differential Equations Lecture Work Solutions 283 - since...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
but argument of F is negative and thus we cannot use (*), instead F ( ct )= h ( t ) G ( ct ) or F ( z )= h ( z c ) G ( z )for z< 0 F ( x ct )= h ( x ct c ) G ( ( x ct )) = h ( t x c ) G ( ct x ) u ( x, t )= F ( x ct )+ G ( x + ct ) = h ( t x c ) G ( ct x ) | {z } zero + G ( x + ct ) | {z } zero
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: since the arguments are positive and (#) is valid u ( x, t ) = h ( t x c ) f o r &lt; x &lt; ct u ( x, t ) = 0 for x ct &gt; 283...
View Full Document

This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

Ask a homework question - tutors are online