Differential Equations Lecture Work Solutions 285

Differential Equations Lecture Work Solutions 285 -...

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Therefore: u ( x, t )= F ( x ct )+ G ( x + ct ) = F ( x ct )+ e x + ct c F ( x ct ) = 1 2 sin ( x ct )+ e x + ct c 1 2 sin ( x ct ) | {z } sin ( x + ct ) = 1 2 sin ( x ct ) 1 2 sin ( x + ct ) | {z } cos ct sin x + e x + ct c u ( x, t
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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