Differential Equations Lecture Work Solutions 289

Differential Equations Lecture Work Solutions 289 -...

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Integrate 1 c F ( ct )+ 1 c G ( ct ) | {z } =0 + 1 c F (0) | {z } =0 1 c G (0) | {z } =0 = Z t 0 h ( τ ) since f = g =0 F ( ct )= c Z t 0 h ( τ ) F ( z )= c Z z/c 0 h ( τ ) F ( x ct )= c Z x ct c 0 h ( τ ) u ( x, t )=
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