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Unformatted text preview: where inside the capacitor s I =0 therefore I A D D A t Q DC A t C Q D A t V D A t A D V t A E dl B C C ' . . r B d I _ B r Where we have used the formula for capacitance of a parallel plate capacitor of plate separation D and plate area A (which is constant over time), D d D A C 2 ' and C CV Q And the relation ship between electrostatic field and electrostatic potential, D V x V E C x x where x is the direction normal to the plates and the potential gradient is uniform between the plates and we have neglected the negative sign since we are dealing with magnitudes only. Therefore we get, I d r I A A rB 2 2 ' 2 which implies that I d r B 2 2 in the c lockwise direction as seen from the left end of the wire....
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 Fall '08
 drake
 Current

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