lecture-04-sql-subqueries

Lecture-04-sql-subqu - SQL Subqueries T M Murali September 1 2010 T M Murali September 1 2010 CS 4604 SQL Subqueries Linear Notation for Relational

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Unformatted text preview: SQL Subqueries T. M. Murali September 1, 2010 T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Linear Notation for Relational Algebra I Relational algebra expressions can become very long. I Use linear notation to store results of intemediate expressions. 1. A relation name and a parenthesised list of attributes for that relation. Use Answer as the conventional name for the final result. 2. The assignment symbol := . 3. Any expression in relational algebra on the right. T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Example of Linear Notation I Name pairs of students who live at the same address. I Normal expression: π S1.Name , S2.Name ( σ S1.Address = S2.Address ( ρ S1 ( Students ) × ρ S2 ( Students ))) T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Example of Linear Notation I Name pairs of students who live at the same address. I Normal expression: π S1.Name , S2.Name ( σ S1.Address = S2.Address ( ρ S1 ( Students ) × ρ S2 ( Students ))) I Linear notation: Pairs(P1, N1, A1, P2, N2, A2) := ρ S1 ( Students ) × ρ S2 ( Students ) Matched(P1, N1, A1, P2, N2, A2) := σ A1 = A2 ( Pairs(P1, N1, A1, P2, N2, A2) ) Answer(Name1, Name2) := π N1 , N2 ( Matched(P1, N1, A1, P2, N2, A2) ). T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Interpreting Queries Involving Multiple Relations SELECT A, B FROM R, S WHERE C; T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Interpreting Queries Involving Multiple Relations SELECT A, B FROM R, S WHERE C; I Nested loops: for each tuple t 1 in R for each tuple t 2 in S if the attributes in t 1 and t 2 satisfy C output the tuples involving attributes A and B . T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Interpreting Queries Involving Multiple Relations SELECT A, B FROM R, S WHERE C; I Nested loops: for each tuple t 1 in R for each tuple t 2 in S if the attributes in t 1 and t 2 satisfy C output the tuples involving attributes A and B . I Conversion to relational algebra: π A , B ( σ C ( R × S )). 1. Compute R × S . 2. Apply the selection operator σ C () to R × S . 3. Project the resulting tuples to attributes A and B . T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Motivation for Subqueries I Find the name of the professor who teaches“CS 4604.” T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Motivation for Subqueries I Find the name of the professor who teaches“CS 4604.” SELECT Name FROM Professors, Teach WHERE (PID = ProfessorPID) AND (Number = ’4604’) AND (DeptName = ’CS’) ; T. M. Murali September 1, 2010 CS 4604: SQL Subqueries Motivation for Subqueries I Find the name of the professor who teaches“CS 4604.” SELECT Name FROM Professors, Teach WHERE (PID = ProfessorPID) AND (Number = ’4604’) AND (DeptName = ’CS’) ; I Do we need to take the natural join of two big relations just to get a relation with one tuple?...
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This note was uploaded on 12/24/2011 for the course CS 4604 taught by Professor Cmmalik during the Fall '08 term at Virginia Tech.

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Lecture-04-sql-subqu - SQL Subqueries T M Murali September 1 2010 T M Murali September 1 2010 CS 4604 SQL Subqueries Linear Notation for Relational

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