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Unformatted text preview: V AV B =R A B E · d r =E R z A z B dz =E ( z Az B ) < 0, b. 3) What is Δ V in volts? a) 7.42 b) 15.7 c) 157. d) 314. e) none of these Note q e =e . Use conservation of energy on electron 1, so, 0 . 5 m ( v 2 Bv 2 A )+e ( V BV A ) = 0. Thus, Δ V = (0 . 5 m/e )( v 2 Bv 2 A ) = 157 V, c. 1 4) What is the speed v in 10 6 m/s? a) 7.42 b) 5.26 c) 3.71 d) 2.14 e) none of these From conservation of energy and the fact that the ﬁnal KE= 0, one gets 0 . 5 mv 2 = e Δ V . So v = q (2 e/m )Δ V = 7 . 42 × 10 6 m/s, a. 5) What is the surface charge density on the surface of the positive plate closest to the negative plate in terms of d, ± , Δ V ? a) ± Δ V d b) 2 ± Δ V d c) ± Δ V 2 d d) Δ V d± d) none of these E = σ/± = Δ V/d , so σ = ± Δ V/d , a. 2...
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This note was uploaded on 12/24/2011 for the course PHYS 2306 taught by Professor Ykim during the Fall '06 term at Virginia Tech.
 Fall '06
 YKim

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