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Unformatted text preview: V AV B =R A B E Â· d r =E R z A z B dz =E ( z Az B ) < 0, b. 3) What is Î” V in volts? a) 7.42 b) 15.7 c) 157. d) 314. e) none of these Note q e =e . Use conservation of energy on electron 1, so, 0 . 5 m ( v 2 Bv 2 A )+e ( V BV A ) = 0. Thus, Î” V = (0 . 5 m/e )( v 2 Bv 2 A ) = 157 V, c. 1 4) What is the speed v in 10 6 m/s? a) 7.42 b) 5.26 c) 3.71 d) 2.14 e) none of these From conservation of energy and the fact that the ï¬nal KE= 0, one gets 0 . 5 mv 2 = e Î” V . So v = q (2 e/m )Î” V = 7 . 42 Ã— 10 6 m/s, a. 5) What is the surface charge density on the surface of the positive plate closest to the negative plate in terms of d, Â± , Î” V ? a) Â± Î” V d b) 2 Â± Î” V d c) Â± Î” V 2 d d) Î” V dÂ± d) none of these E = Ïƒ/Â± = Î” V/d , so Ïƒ = Â± Î” V/d , a. 2...
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 Fall '06
 YKim
 Electrostatics, Electric charge, âˆ†V, potential difference âˆ†v, vB âˆ’ vA, large area parallel

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