review2ans - MAC 1105 Test 2 Review Summer B 2011 Solutions...

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Unformatted text preview: MAC 1105 Test 2 Review, Summer B 2011 - Solutions 1. (a) (d) 2. (a) 2(x − 5) x−1 (b) Modified answer = −x2 + 3x + 13 (x + 4)(x − 2)(x + 1) −1 5x + 7 (b) 3. (a) −12 + 18i (e) (c) 2x + 11 (x + 3)2 2(2x − 3) 3(6 + x) x+3 2(x + 18) (b) 16i 4 x (c) 14 − x 2 (c) i (d) 5i (e) 2 + 9i 5 4. False −7 ± (b) x = 3 5. (a) x = −5 6. x = 0, 3; 7. t = √ 2 (c) x = −8 (d) x = 1, no solution A−P Pr 8. (a) x = −15, 1 (b) x = 1 ± √ 6 √ 1 3 9. (a) discriminant = −3 so 2 complex solutions; x = ± i 2 6 1 (b) discriminant = 0 so 1 real solution; x = − 6 √ 14 i (c) discriminant = −56 so 2 complex solutions; x = ± 2 1 10. (a) x = −2, − , 2 2 √ √ 11. x = ± 3, ±i 3 12. (a) x = −2, 4 13. x = − 3 4 14. (a) x = − (b) x = −2, 0, 1 2 (c) x = ±1, ±7 (b) x = −1, 3 4x − 1 = −4 13 ,y = 2 4 (b) x = 3, y = 2 1 1 (c) x = , y = − 3 6 15. No Solutions 16. length = 12 feet, width = 15 feet; 2 17. $460 18. $30,000 in CD and $30,000 in bonds Perimeter = 39 feet 1 2 (e) x = −1, 16 ...
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This note was uploaded on 12/27/2011 for the course MAC 1105 taught by Professor Picklesimer during the Fall '10 term at University of Florida.

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