05_3069_Key - -1 and 1, since those are the two numbers...

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MAC 1147 (3069) - Quiz #5 Name: Key For full credit, you must show all work and circle your final answer. 1 Use long division OR synthetic division to divide. (1.5 points) (3 x 3 - 16 x 2 - 72) ÷ ( x - 6) 3 x 2 + 2 x + 12 x - 6 ) 3 x 3 - 16 x 2 - 72 - 3 x 3 + 18 x 2 2 x 2 - 2 x 2 + 12 x 12 x - 72 - 12 x + 72 0 3 - 16 0 - 72 6 18 12 72 3 ±* · 6 2 ? + ± ±* · 6 12 ? + ± ±* · 6 0 ? + 2 Write the quotient in standard form. (1.5 points) ( Hint: The standard form of a complex number is a + bi , where a and b are real numbers.) 13 1 - i 13 1 - i = 13 1 - i ± 1 + i 1 + i ² = 13 + 13 i 1 - i 2 = 13 + 13 i 2 = 13 2 + 13 2 i. 3 Find the domain of the function and identify any vertical or horizontal asymptotes. (2 points) f ( x ) = x + 1 x 2 - 1 f ( x ) = x + 1 x 2 - 1 = x + 1 ( x + 1)( x - 1) . So, the domain is all real numbers except
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Unformatted text preview: -1 and 1, since those are the two numbers which make the denominator equal zero. The horizontal asymptote is at y = 0 because the denominator has a higher power of x than the numerator. The vertical asymptote is at x = 1. Note that there is not a vertical asymptote at x =-1 because the x + 1 terms cancel, so there is just a hole in the function at x =-1. University of Florida Honor Code: On my honor, I have neither given nor received unauthorized aid in doing this assignment. Signature...
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This note was uploaded on 12/27/2011 for the course MAC 1147 taught by Professor German during the Summer '08 term at University of Florida.

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