Unformatted text preview: and x ≥ is measured in appropriate units of brightness. Should the pupil have a larger area when x = 0 or when x = 32 ? How may times larger is it? The equation above can be solved for the variable x 2 / 5 . Show that x = ± R40 244 R ² 5 / 2 . For what xvalue will R be 10 square millimeters (round to the nearest tenth)? Note that x is not a real number for some R values because of the square root. Solve an inequality in order to determine the values of R for which there is a real solution ( x,R ) . What seem to be the smallest and largest possible areas R for the pupil?...
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 Spring '08
 Smith
 Calculus, Equations, Distance Formula, square millimeters

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