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Unformatted text preview: Instead of using Ch.1, some people guessed, but this didnt usually work out. Re-member that dim S + dim S = 3, so the answer should be a list of two vectors. 2) Since L : P 3 P 3 , and dim P 3 = 3, the matrix should be 3x3. Compute L (1) = 0 = [0 0 0] T which is column 1, etc. Get A = 1 2 3) These are in the text, except that 3b) was HW: Assume A = S-1 BS . Cube both sides and cancel the SS-1 s and get A 3 = S-1 B 3 S . So, A 3 is similar to B 3 . 1...
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- Spring '09