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lec24-33 - ii excretion = 125 mg inulin per min clearance...

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KIN 205: Chapter 19, The Kidneys: Excretion = filtration - reabsorption + amount secreted Clearance: an abstract concept that describes how many mL of plasma passing through the kidneys have been totally cleared of a substance in a given period of time. Clearance = (urine excretion of the substance [mg/min]) / (plasma concentration of the substance [mg/mL]) where : urine excretion = (urine flow) x (urine concentration) e.g. INULIN : comes out in the filtrate and it is neither reabsorbed nor secreted. i) inulin injected at 100 mg/dL plasma
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Unformatted text preview: ii) excretion = 125 mg inulin per min. clearance = (125 mg / min) / (100 mg / 100 mL plasma) = 125 mL plasma / min Filtration = plasma concentration X GFR ∴ GFR = Filtration / plasma concentration for inulin, filtration = excretion ∴ , GFR = clearance = (inulin excretion) / (plasma inulin) Inulin can therefore be used to determine GFR. This can then be used to determine filtration rates of other substances . B. Filtration, Reabsorption, Secretion, Excretion...
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