Phys105A_W09_HW3sols

Phys105A_W09_HW3sols - Taylor 3.4 For the sake of...

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Unformatted text preview: Taylor 3.4 For the sake of definiteness lets say that the cart moves in the the positive x direction, and the hobos in the negative x direction. We are told the magnitude of the hobos speed relative to the car so, using the notation where v A/B is the velocity of A relative to B , we have | v H/C | = u v H/C =- u x . (1) Use a couple of basic facts about relative velocities in order to find the velocity of the cart relative to the earth and the velocity of the hobo relative to the earth, v H/C = v H/E + v E/C v E/C =- v C/E v H/C = v H/E- v C/E If I denote the hobo velocity relative to the ground as- v h x ( v h is the speed) and the cart velocity relative to the ground as v c x ( v c is the speed), then the last equation above says- u x =- v h x- v c x v h = u- v c (a) Conservation of momentum initial p = 0 x (2) final p =- 2 m h ( u- v c ) x + m c ( v c ) x (3) Setting initial p equal to final p and rearranging v c = 2 m h 2 m h + m c u (4) (b) Break this answer into two parts. First solve for when just one hobo has jumped. Then using that information, solve for whenone hobo has jumped....
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This note was uploaded on 12/27/2011 for the course PHYS 105a taught by Professor Van,d during the Fall '08 term at UCSB.

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Phys105A_W09_HW3sols - Taylor 3.4 For the sake of...

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