Homework6sol.fall10

# Homework6sol.fall10 - ME 560 Kinematics Fall Semester 2010...

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ME 560 Kinematics Fall Semester 2010 Homework No. 6 Wednesday, October 27th This homework set is based on Chapter 7 of the required text by Uicker, et al., see Sections 7.1 to 7.11, pages 330 - 361. Problem 1. Solve Problem 7.1, see page 362. Problem 2. Solve Problem 7.2, see page 362. Problem 3. Solve Problem 7.3, see page 362. Problem 4. Solve Problem 7.10, see page 362. Problem 5. Solve Problem 7.11, see page 362.

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2 Solution to Homework Set 6. Problem 7.1 . Find the diametral pitch of a pair of gears having 32 and 84 teeth, respectively, whose center distance is 3.625 in. The sum of the radii of the two pitch circles can be written as 3 2 23 32 84 3.625 in 22 2 N N RR PP P + += + = = Therefore, the diametral pitch of the pair of gears is () 116 teeth 16 teeth/in 2 3.625 in P == Ans. Problem 7.2. Find the number of teeth and the circular pitch of a 6-in pitch diameter gear whose diametral pitch is 9 teeth/in. The number of teeth can be written as ( )( ) (2 ) 9 teeth/in 6.0 in 54 teeth NPR = Ans. Therefore, the circular pitch of the pair of gears is ( ) 9 teeth/in 0.349 1 in/tooth pP ππ = Ans.
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## This note was uploaded on 12/27/2011 for the course ME 560 taught by Professor Na during the Fall '10 term at Purdue.

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Homework6sol.fall10 - ME 560 Kinematics Fall Semester 2010...

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