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IMG_0001_NEW_0044

# IMG_0001_NEW_0044 - AH Ase.s kJ(u'o kJ c-59.5 kJ d-l l9 kJ...

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AE=c w'1/ 15. rn an isothermal process, the pressure on one -or. oru.da&n**"*" i" *rffii"lil*.5;-{* to 100.0 afrnat25"C. I fv, LV nvt =>( (n nf) ) Calculate w. *;,'* c)o d) -23.5 kJ e) 23.5 kJ 16. In an isothermal process, the pressure on one mole of an ideal monatomic gas suddenly changes from 4'00 atm to 100.0 atrn at 250c. Calculate AE. a) -59.5 kJ b) l19kJ c) 59.5 kJ dbp kJ ilnone of these \6i^an isothermal process, the pressure on one mole of an ideal monatomic gas suddenly changes from 4'00 atm -v) = ,) M bE=r{[email protected] = ^-616 is a)o 9l;l d) -3e.4 e) -17.1 Calculate AGr (25'C) in kJ/mol for Nz at 1000 Aq : Ah" +kI4,nt4 .= g.lrvvr -ftra\$ _4S 4 -vi) W-ot -to 100.0 atn at 250c. Calculate
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Unformatted text preview: AH. Ase.s kJ (u'o kJ c) -59.5 kJ d) -l l9 kJ e) none ofthese lg. In an isothermal process, the pressure on one mole of an ideal monatomic gas suddenly changes from 4'00 atm to 100.0 atrn at 25"C. Calculate AS. a) -20.5 JIK b) 2o.s J/K c)26.8I|K Aftzo.sttK Vnon. ofthese htffi##l process, the pressure on one mole of an ideal monatomic gas suddenly changes from 4'00 atm to-1w= -nrlr/9. .{ff = -^Frhfr") 100.0 atrn at25"C. 19. Calculate AG. a)0kJ b) 59.5 kJ 9";'1" e) none ofthese 20. The standard free energy of formation of N2 @) at25"C is zero' atn. Assume ideal gas behavior' aF-Ah =A&/* FT-l^&, = t 7.r L1 z'*1...
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