Test 1 Answers

Test 1 Answers - Test 1 Spring 2011 MATH 1550 - 19 p. 1...

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Unformatted text preview: Test 1 Spring 2011 MATH 1550 - 19 p. 1 Name: Show several steps for each calculation problem. Partial credit will be given. Read the directions for each problem and solve the problem using the stated method. Be sure to check for indeterminate form on limit problems. Check your work if you have time. Good luck. 1. (10 points) Assume lim y → c g ( y ) =- 2 and lim y → c h ( y ) = 3. Use the basic limit laws to calculate lim x → c 2 · h ( y ) + g ( y ) g ( y )- 3 · h ( y ) . Answer We can substitute the given values for the limits of g ( x ) and h ( x ) at c to get: lim x → c 2 · (3) + (- 2) (- 2)- 3 · (3) = 6- 2- 2- 9 =- 4 11 2. (10 points) For lim x →− 2 (3 x + 2)( x 2 + 5), evaluate the limit or state that it does not exist Answer The function is a product of polynomials, thus it is continuous everywhere and we can substitute x =- 2 to get lim x →− 2 (3 x + 2)( x 2 + 5) = (3(- 2) + 2)((- 2) + 5) =- 4 · 9 =- 36 3. (10 points) For lim x → sin x 9 x , evaluate the limit or state that it does not exist Answer We can separate this function into the product 1 9 · sin x x and we get that lim x → sin x 9 x = 1 9 · lim x → sin x x = 1 9 · 1 = 1 9 Test 1 Spring 2011 MATH 1550 - 19 p. 2 4. (10 points) For lim x → 4 parenleftbigg 1 √ x- 2- 4 x- 4 parenrightbigg , evaluate the limit or state that it does not exist., evaluate the limit or state that it does not exist....
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This note was uploaded on 12/28/2011 for the course MATH 1550 taught by Professor Wei during the Spring '08 term at LSU.

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Test 1 Answers - Test 1 Spring 2011 MATH 1550 - 19 p. 1...

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