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Problem Bohr atom simple one

# Problem Bohr atom simple one - 7 m-1 hcR = 6.626 x 10-34...

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Problem: What is the energy of an electron in the =3 energy state of a hydrogen atom? Solution: E = hν = hc/λ According to the Rydberg formula: 1/λ = R(Z 2 /n 2 ) where R = 1.097 x 10 7 m -1 Z = Atomic number of the atom (Z=1 for hydrogen) Combine these formulas: E = hcR(Z 2 /n 2 ) h = 6.626 x 10 -34 J·s

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c = 3 x 10 8 m/sec R = 1.097 x 10
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Unformatted text preview: 7 m-1 hcR = 6.626 x 10-34 J·s x 3 x 10 8 m/sec x 1.097 x 10 7 m-1 hcR = 2.18 x 10-18 J E = 2.18 x 10-18 J(Z 2 /n 2 ) E = 2.18 x 10-18 J(1 2 /3 2 ) E = 2.18 x 10-18 J(1/9) E = 2.42 x 10-19 J Answer: The energy of an electron in the n=3 energy state of a hydrogen atom is 2.42 x 10-19 J....
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Problem Bohr atom simple one - 7 m-1 hcR = 6.626 x 10-34...

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