Applied Finite Mathematics HW Solutions 5

# Applied Finite Mathematics HW Solutions 5 - EXERCISES 1.1...

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Unformatted text preview: EXERCISES 1.1 19- Β§(\$β5)_+4:= %(2β32)+1 r) G) (a: β 5) + 6(4) = 6 (g) (2 β 3.1;) +6(1) 2(3~5)+24=2β3\$+_6 '23β10+24=3β32: 23+3az=8β14 53:2β6 β6 \$0.23 β5β5 The original equation was linear. 20- 3(1β2m)+i=%(32:β1)+1 E 1 1 , 1 20(3)(1β2:z)+20 Z =20 5 (3.2:β-1)+20 2 60(1β23)+5=4(32:β1)+10 60β1202:+5=12:cβ4+10 β1203: +65 =123+6 β1203 β- 12.1: = 6 β- 65 β132:c = β59 _ β59 _ 59 _ β132 _ 132 The original equation was linear. 21. 5 _ 5 1 = 33β2 3 . 3 7 + 2 +2: + 42 (-3.) β 42 (g) + 42(1) = 42 (333) + 42(2) +_42(3) 142β62 +42 =63z+42z +126 ' 32: + 42 = 1052: +126 82 β 1052. = 126 4 42 β-972=84 z:ο¬ia_E . β97 97 The original equation was linear. _ 22. 2(3β1)+6=4x+1β2(4+3) ' 23*2+6=42:+1-8β2:c 23+4=22:β7 23β29;: β-7β4 0=-11 The eqnation has 'no solution. The original equation was not linear. 23. . _3x+4_+(1β4m)=1+xβ2(a:;16) 33+.4+1β4m=1+3β22:+32 βa:+5 : β\$+33 β-:1:βlβ3: =33β5 0:23 The equationhas no solutions. The original equation was not linear. 'lβhismatedal hasbeenrepmduoed in awordanwwiο¬icopyrigln law by the University ofMani'toba Bookstore. Furlher remodudim in narl or in a." as drir'llurmnhlhο¬nrl ...
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