{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Applied Finite Mathematics HW Solutions 12

Applied Finite Mathematics HW Solutions 12 - 1o EXERCISES...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 1o _ _ EXERCISES 1.3 21 . To find the point of intersection, we multiplyr the first equation by 3 and the second equatiou ' byz. 9x — 6y 2 12, 103 + 6y =14. When we add these equations together, we get 26 When we substitute this into the first equation, 25 7'8 2 l 3(E) —2y—4 ls» ~2y24—fi=~fi ——-‘* 9—K)- The point of intersection is (26/ 19, 1 / 19). The lines and point of intersection are shown in the right figure above. 22. To find the point of interSection, we multiply the first equation by 4 and the second equation by 5. 83: + 20y = —12, 15.1: — 20y = 15. When we add these equations together, we get ' 3 '-When we substitute this into the first equation, ' 3 . 6 7'5 __ 15 The point of intersection is (3/23, —15/23). The lines and point of intersection are shown in the left figure below. 23. To-find the point of intersection, we multiply the second equation by 3, 123 +133; = 2?, ' 12x — 15;; = ~30. When we subtract these equations, we get This material has been reproduced in accordance with cogyright law by the Univclsity of Manitoba Bookstore. Further repmdudim in oar: m- in fim ,‘g glfinflu was”: /"‘\. ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern