{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Applied Finite Mathematics HW Solutions 96

# Applied Finite Mathematics HW Solutions 96 - 94 EXERCISES...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ' 94 EXERCISES 5.3 17' 18. 19. 20. 21. T1131: mania-in] I'll-us luau mam-lunar! :n swan-loam un'lh mun-ink! In... In: il-u I Ink-mun ni‘ll’anﬂnl‘n Dnnbnlm 'L‘...t-'l.....— With P = 100, 2‘ = 5, m = 12, and n = 120, the value of the annuity on May 1, 2014 is 5 120 100[(1+ 100.12) —1] 5/1200 This amount collects one month's interest from May 1, 2014 until June 1, 2014. Using formula 5.2 with P = 15 528.23, 1' = 5, m = 12, and n = 1, the accumulated value is 5 100-12 With P : 200, 2' = 6, m 2. 12, and n = 43, formula 5.4 gives the value of the annuity on October 1, 2014 ' 6 43 200 l(1+100_12) —1] 6/1200 With P =‘500, i = 5, m = 4, and n = 28, formula 5.4 gives the value of the annuity on 5 23 500 (”100-4) — A120 = = 15 523.23. 01 = 15,528.23 (1 + ) = 15 592.93. A43 = = 9567.91. October 1, 2010 A23 = 5,400 = 16 639.69. With P = 50, 1: = 5, m = 12, and An = 10 000, formula 5.4_ gives 5 n 50 [(1 + 100- 12) _ 1] 1205 " 10 000(5) 125 10000=———————— :5 50 — —1=_=—. 5/1200 1200 1200 3 Thus, (a 1,1,1. E -2 240 "50 3 "6 A calculator shows that 145 146 (g) :15. 1.. (3.33.) 21.335. You-will have at least \$10,000 after the 146‘” deposit. This is on June 1, 2016. With P = 500, 3': 6, m = 12, and An = 500 000, formula 5.4 gives 241 n 11 (E) —-F—-1.833. 6 n ' . 500 [(1 + — 1.] n _ 100 - 12 201 _ 500 000(6) _ 500000— 6/1200 ==> 500 [(200) —1] —- 1200 —25[}[}. Thus, 2—06 - 500 E A calculator shows that 359 I 380 (%) = 5.99 and (-33%) = 6.02. You will have \$500,000 after the 360“1 deposit. This is when you are 55. 1| 11 (201) _1:2500:5 :2} (201) =6. Judi” :n a...“ M L. A." :. .|_'.al-. .._I..:l.:¢...I r‘"\ I'M-.0 ...
View Full Document

{[ snackBarMessage ]}