Sample Final Answers

Sample Final Answers - Sample final type questions CHM2120A...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Sample final type questions CHM2120A 1. Show the mechanism for this reaction and explain which side the equilibrium lies on. O + HO O H O + O O H pKa = 8 pKa = 22 more stable conjugate base - acid has a lower pKa eq favors this side 2. Rank these electrophiles in order of increasing reactivity toward hydroxide ions. Br O S CH 3 O O I Cl O O 2 N 1 two en atoms make the carbon very electrophilic, no backbonding from chlorine 2 3 4 allylic system plus great LG, primary carbon has very little steric hinderance iodine is a good leaving group but secondary alcohol adds steric hinderance alkene are poor electrophile because they are very stable functional groups 3. Rank these aromatic compounds from least reactive to most reactive with SO 3 , H 2 SO 4 and show what the products will be. S S O O Cl OMe OMe least reactive 1 strong EWG most reactive 2 strong EDG, 1 weak EWG 2nd most reactive 1 strong EDG 3rd most reactive S O O SO 3 H S SO 3 H SO 3 H Cl OMe OMe SO 3 H
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
4. Which of these nucleophiles will need activation to add reversibly to N-methylketamine and
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/22/2011 for the course CHM 2120 taught by Professor Dr.flynn during the Spring '10 term at University of Ottawa.

Page1 / 9

Sample Final Answers - Sample final type questions CHM2120A...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online