Mid3 Problem 2 solution

Mid3 Problem 2 solution - Mid 3 Pr 2 Solution tM in years...

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Unformatted text preview: Mid 3 Pr. 2 Solution tM in years ∆ x = /4= /2 2 1 ct ∆ β= Tanφ=1/2 s =9−4 =5ly 2 A B 2 φ sAB = 5ly sAC =0 lies on line cone B and C simultaneous in Mary’s frame. C first in Jim’s frame Jim’s frame with beta 1/2 ...
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This note was uploaded on 12/28/2011 for the course PHYSICS 270 taught by Professor Drake during the Fall '08 term at Maryland.

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