This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: v = e v F = m a = qvB [ e ( e z )] = qvB e r Central force mv 2 / r = qvB r = mv / qB Particle gyroradius proportional to m D 2 / D 1 = m 2 / m 1 m 2 = ( D 2 / D 1 ) m 1 m 2 is heavier and has a larger gyroradius D 2 D 1 x y v B c. If possible, find the magnitude (in terms of the given variables) and direction of an electric field that can make the whole beam go through the region in a straight line instead of the shown halfcircles. If it is not possible, explain why not . (7) In order to move along the xaxis the magnetic force should be balanced by the electric force so that F = q [ E + v e x ( e z ) B ] = E = vB ( e x e z ) = vB e y...
View
Full
Document
This note was uploaded on 12/28/2011 for the course PHYSICS 270 taught by Professor Drake during the Fall '08 term at Maryland.
 Fall '08
 drake
 Charge

Click to edit the document details