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Unformatted text preview: v = ˆ e θ v F = m a = qvB [ ˆ e × ( − ˆ e z )] = − qvB ˆ e r Central force mv 2 / r = qvB r = mv / qB Particle gyroradius proportional to m D 2 / D 1 = m 2 / m 1 m 2 = ( D 2 / D 1 ) m 1 m 2 is heavier and has a larger gyroradius D 2 D 1 x y v B c. If possible, find the magnitude (in terms of the given variables) and direction of an electric field that can make the whole beam go through the region in a straight line instead of the shown halfcircles. If it is not possible, explain why not . (7) In order to move along the xaxis the magnetic force should be balanced by the electric force so that F = q [ E + v ˆ e x × ( − ˆ e z ) B ] = E = vB ( ˆ e x × ˆ e z ) = − vB ˆ e y...
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 Fall '08
 drake
 Charge, Magnetic Field, Electric charge, magnetic field region

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